Tolong Bantu beri jawaban
Jawaban:
u = x³+1...x³ = u-1
du = 3x² dx....x² = du/3 dx
= int u¹⁰ x³.x² dx
= int u¹⁰ (u-1) du/3dx. dx
= int ⅓ u¹⁰ (u-1) du
= ⅓ int u¹¹ - u¹⁰ du
= ⅓. { ¹/12 u¹² - ¹/11 u¹¹ }
= ¹/36 u¹² - ¹/33 u¹¹
= ¹/36 (x³+1)¹² - ¹/33 (x³+1)¹¹
[tex] [/tex]
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